
Slope-intercept form introduction - Khan Academy
Learn about the slope-intercept form of two-variable linear equations, and how to interpret it to find the slope and y-intercept of their line.
Linear equations & graphs | Algebra 1 | Math | Khan Academy
Let's explore different ways to find and visualize slopes and intercepts, and how these concepts can help us solve real-world problems. **Unit guides are here!**
Intercepts of lines review (x-intercepts and y-intercepts) (article ...
The x-intercept is where a line crosses the x-axis, and the y-intercept is the point where the line crosses the y-axis. Thinking about intercepts helps us graph linear equations.
Slope and y-intercept from equation (video) | Khan Academy
Let's say we had y is equal to negative seven, what's the slope and y-intercept there? Well, once again, you might say, hey, this doesn't look like what we had up here, how do we figure out the …
Intro to intercepts (video) | Khan Academy
Learn what x- and y-intercepts are. The equations used in this video are y = 0.5x - 3 and 5x + 6y = 30.
Intercepts from a table (video) | Khan Academy
Since the table represents a line, there's a constant rate of change of y with respect to x. So we can find that pattern and fill in skipped values from the table to find the y-intercept.
Intercepts from a graph (practice) | Khan Academy
Intercepts from a graph CCSS.Math: 8.F.A.1, HSA.REI.D.10, HSF.IF.C.7, HSF.IF.C.7.a Google Classroom Microsoft Teams
Intercepts of lines review (x-intercepts and y-intercepts)
You can always find the X-intercept by setting Y to 0 in the equation and solve for X. Similarly, you can always find the Y-intercept by setting X to 0 in the equation and solve for Y.
Worked example: intercepts from an equation - Khan Academy
Let's find the x- and y-intercepts of the equation 2y + 1/3x = 12, where a line crosses the x-axis (the x-intercept) and the y-axis (the y-intercept) on a graph. To find the x-intercept, we make y …
Graphing quadratics: vertex form | Algebra (video) | Khan Academy
Once you've graphed the vertex, move 1 unit to the left and right of the vertex to get two new "x" values to find more points to complete your graph. For each new value of "x", you use it in the …