
Question #16bc5 - Socratic
Another way to determine which graph is on top is to sketch the graphs. It is also possible to get the correct answer by choosing an order of subtraction and the making the final answer …
How do you graph # f (x)=x^2+2#? - Socratic
So, #f (x)# is a concave up parabola and has an absolute minimum value of #2# at #x=0#. The graph of #f (x)# is ahown below.
How do you graph and find the vertex for # y=6abs (x-7)
1 Answer Alan P. May 27, 2015 #y=6abs (x-7)# When #x<7# #y = 6 (7-x) = 42-6x# which is the equation of a straight line terminating at # (7,0)# When #x>=7# #y=6 (x-7) = 6x-42# which is …
Additive Inverses and Absolute Values - Socratic
Questions What are absolute values? What is the absolute value of -10 and 10? How do you know that the additive inverse of -20 is 20? How do you evaluate #|2-8|#?
I've been struggling in this sound wave question for more
The amplitude is the maximum absolute value of the wave. For sin or cos functions, the amplitude is the coefficient before the trigonometrics.Therefore the amplitude for y=1/4cos ( (2pi)/3theta) …
Question #9ff5f - Socratic
Question #9ff5f Algebra Linear Inequalities and Absolute Value Multi-Step Inequalities
Question #810fc - Socratic
Mar 25, 2016 · The action taking place is that you are looking at a standard graph of #tan (x)# and noting the y value on that graph for #2x#. You are then going back to the graph you are …
How do you graph the system of linear inequalities - Socratic
How do you graph the system of linear inequalities y ≥ − 4 and y <− 2x + 10? Algebra Linear Inequalities and Absolute Value Linear Inequalities in Two Variables
What is the solution set for abs (2x – 4) = 10? | Socratic
Aug 29, 2015 · What is the solution set for |2x– 4| = 10? Algebra Linear Inequalities and Absolute Value Absolute Value Equations
By applying the rules for natural logarithms, how could 2ln|x| be ...
ln(x^2) Apply the power rule for logarithms 2ln|x|=ln(|x|^2) As we know, the square of a positive or negative number is always positive, so |x|^2=x^2 and the answer becomes ln(x^2).